Interview Questions

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main()
{
char *p;
printf("%d %d ",sizeof(*p),sizeof(p));
}
Ans: 

1 2
The sizeof() operator gives the number of bytes taken by its operand. P is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2.

main()
{
extern int i;
i=20;
printf("%d",i);
}
Ans: 

Linker Error : Undefined symbol '_i'.
extern storage class in the following declaration,extern int i;specifies to the compiler that the memory for i is allocated in some other program and that address will be given to the current program at the time of linking. But linker finds that no other variable of name i is available in any other program with memory space allocated for it. Hence a linker error has occurred.

main()
{
int c[ ]={2.8,3.4,4,6.7,5};
int j,*p=c,*q=c; for(j=0;j<5;j++)
{
printf(" %d ",*c); ++q; } for(j=0;j<5;j++)
{
printf(" %d ",*p); ++p;
}
}
Ans: 

2 2 2 2 2 2 3 4 6 5
Initially pointer c is assigned to both p and q. In the first loop, since only q is incremented and not c , the value 2 will be printed 5 times. In second loop p itself is incremented. So the values 2 3 4 6 5 will be printed.

main()
{
static int var = 5;
printf("%d ",var--);
if(var) main();
}
Ans: 

5 4 3 2 1.
When static storage class is given, it is initialized once. The change in the value of a static variable is retained even between the function calls. Main is also treated like any other ordinary function, which can be called recursively.

main()
{
float me = 1.1;
double you = 1.1;
if(me==you)
printf("I love U");
else
printf("I hate U"); }
Ans: 

I hate U
For floating point numbers (float, double, long double) the values cannot be predicted exactly. Depending on the number of bytes, the precession with of the value represented varies. Float takes 4 bytes and long double takes 10 bytes. So float stores 0.9 with less precision than long double Rule of Thumb: Never compare or at-least be cautious when using floating point numbers with relational operators (== , >, <, <=, >=,!= ) ..

main()
{
char s[ ]="man";
int i;
for(i=0;s[ i ];i++)
printf("\n%c%c%c%c",s[ i ],*(s+i),*(i+s),i[s]);
}
Ans: 

mmmm aaaa nnnn.
s[i], *(i+s), *(s+i), i[s] are all different ways of expressing the same idea. Generally array name is the base address for that array. Here s is the base address. i is the index number/displacement from the base address. So, indirecting it with * is same as s[i]. i[s] may be surprising. But in the case of C it is same as s[i].

void main()
{
int const * p=5; printf("%d",++(*p));
}
Ans: 

Compiler error: Cannot modify a constant value.
p is a pointer to a "constant integer". But we tried to change the value of the "constant integer".